Need help finding the inverse of the function:
y=(x 1)
also written as: y=(x 1)^3
y = cube_root_of(x) - 1
For instance suppose x = 5
Then (your function) y = (5 1) ^3 = 6^3 = 216
My function: y = cube_root_of(216) - 1 = 6 - 1 = 5
Switch y with x and x with y^-1 (Y inverse). It should look like this: X=((Y^-1) 1))^3. Then take the cube root of both sides of the equation. Cuberoot(x)=(Y^-1) 1 Subtract one from each side of the equation and you get Y^-1=cuberoot(x)-1. That is your final answer.
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